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A body of mass 1 is executing simple harmonic motion. Its displacement y(cm) at t seconds is given by `y = 6 sin (100t + pi//4)` . Its maximum kinetic energy isA. 6 JB. 18 JC. 24 JD. 36 J |
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Answer» Correct Answer - B a=6 cm , `omega=100 "rad" s^(-1)` `K_("max")=(1)/(2)momega^(2)a^(2)=(1)/(2)xx 1 xx (100)^(2)xx (6xx 10^(-2))^(2)=18 J` |
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