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A body of mass 1 kg is attached to one end of a wire and rotated in a horizontal circle of diameter 40cm with constant speed of 2m/s What is the area of cross section of the wire if the stress developed in the wire is 5 xx 10^6 N/m^2 . |
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Answer» Solution :`F = T = (mv^2)/r = (1 xx 4)/(0.2)= 20N` `STRESS = F//A THEREFORE A = F/(stress) = 20/(5 xx 10^6)` `4 xx 10^(-6) m^2 = 4mm^2` |
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