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A body of mass 1 kg is executing S.H.M. given by x=6cos(100t+pi//4) cm, what is its maximum K.E. ? |
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Answer» Solution :Here `""OMEGA=100` rad/s. `:.""` r = 6 CM = 0.06 m. Max K.E. `=(1)/(2)m omega^(2)r^(2)=(1)/(2)xx1xx(100)^(2)xx((6)/(100))^(2)` `=18` J. Hence CORRECT choiceis (a). |
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