1.

A body of mass 1 kg is moving in a vertical circular path of radius 1 m. The difference between the kinetic energies at its highest and lowest position isA. 20 JB. 10 JC. `4sqrt5` JD. `10(sqrt5-1)` J

Answer» Correct Answer - A
Difference between the kinetic energies at its highest and lowest positions is
`2mgr=2xx1xx10xx1=20J`


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