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A body of mass 1 kg is moving in a vertical circular path of radius 1 m. The difference between the kinetic energies at its highest and lowest position isA. 20 JB. 10 JC. `4sqrt5` JD. `10(sqrt5-1)` J |
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Answer» Correct Answer - A Difference between the kinetic energies at its highest and lowest positions is `2mgr=2xx1xx10xx1=20J` |
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