A body of mass 1 kg is thrown vertically upwards with initial K.E. of 98 joule. The height at which its energy is reduced to half will be

A body of mass 1 kg is thrown vertically upwards with initial K.E. of

1.	A body of mass 1 kg is thrown vertically upwards with initial K.E. of 98 joule. The height at which its energy is reduced to half will be
Answer» 2.5 m 1.25 m 5 m 10 m Solution :Gain in P.E. = LOSS in K.E. =98-49=49 J. `mgh=49 J impliesh=(49)/(1xx9.8)=5 m`.

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A body of mass 1 kg is thrown vertically upwards with initial K.E. of 98 joule. The height at which its energy is reduced to half will be

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