A body of mass 10 kg is raised to height 10 m above the ground with an acceleration of 1.5 m//s^(2). The work done in this case taking g = 10 ms^(-2) is:

A body of mass 10 kg is raised to height 10 m above the ground with an

1.	A body of mass 10 kg is raised to height 10 m above the ground with an acceleration of 1.5 m//s^(2). The work done in this case taking g = 10 ms^(-2) is:
Answer» 1000 J 1100 J 1150 J None of these Solution :F-mg=ma F=m(g+a) WORK DONE,`W=m(g+a)XXH` `10xx(10+1.5)xx10=1150 J`

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A body of mass 10 kg is raised to height 10 m above the ground with an acceleration of 1.5 m//s^(2). The work done in this case taking g = 10 ms^(-2) is:

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