1.

A body of mass 10 mg is moving with a velocity of 100 ms^(-1).The wavelength of de-Brogile wave associated with it would be (h = 6.63 xx 10^(-34) Js)

Answer»

`6.63 XX 10^(-35) m`
`6.63 xx 10^(-34)` m
`6.63 xx 10^(-31)` m
`6.63 xx 10^(-37)` m

Solution :`m = 10 mg = 10 xx 10^(-3) g`
= `10 xx 10^(-6)` kg = `10^(-5)` kg
`v = 100 ms^(-1)`, de Brogile, `lambda = ?`
`h = 6.63 xx 10^(-34) Js^(-1)`
de Brogile RELATION, `lambda = (h)/(mv)`
`lambda = (6.63 xx 10^(-34)Js^(-1))/(10^(-5) xx 100) = (6.63 xx 10^(-34))/(10^(-3))`
= `6.63 xx 10^(-31)` m.


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