A body of mass 100 grams is tied to one end of a string and revolved a

1.	A body of mass 100 grams is tied to one end of a string and revolved along a circular path in the horizontal plane. The radius of the circle is 50 cm. If the body revolves with a constant angular speed of 20 rad/s, find the 1. period of revolution 2. linear speed 3. centripetal acceleration of the body.
Answer» Data : m = 100 g = 0.1 kg, r = 50 cm = 0.5 m, ω = 20 rad/s 1. The period of revolution of the body, 2. Linear speed, v = ωr = 20 × 0.5 = 10 m/s 3. Centripetal acceleration, a_c = ω² = (20)² × 0.5 = 200 m/s²

A body of mass 100 grams is tied to one end of a string and revolved along a circular path in the horizontal plane. The radius of the circle is 50 cm. If the body revolves with a constant angular speed of 20 rad/s, find the 1. period of revolution 2. linear speed 3. centripetal acceleration of the body.

Answer»

Data : m = 100 g = 0.1 kg, r = 50 cm = 0.5 m,

ω = 20 rad/s

1. The period of revolution of the body,

2. Linear speed, v = ωr = 20 × 0.5 = 10 m/s

3. Centripetal acceleration,

a_c = ω² = (20)² × 0.5 = 200 m/s²

Discussion

No Comment Found

Related InterviewSolutions

State with reason if the statement is true or false : A wheel moving down a perfectly frictionless inclined plane will undergo slipping (not rolling) motion.
What happens when a ballet dancer stretches her arms while taking turns?
If the Earth suddenly shrinks so as to reduce its volume, mass remaining unchanged, what will be the effect on the duration of the day?
Do we need a banked road for a two wheeler? Explain.
What about the kinetic friction between the road and the lyres?
If friction is zero, can a vehicle move on the road? Why are we not considering the friction in deriving the expression for the banking angle?
We have mentioned about ‘static friction’ between road and tyres. Why is it static friction? What about kinetic friction between road and tyres?
A metre gauge train is moving at 72 kmph along a curved railway track of radius of curvature 500 m. Find the elevation of the outer rail above the inner rail so that there is no side thrust on the outer rail.
A railway locomotive enters a stretch of track, which is in the form of a circular arc of radius 280 m, at 10 m/s and with its speed increasing uniformly. Ten seconds into the stretch its speed is 14m/s and at 18s its speed is 19 m/s.Find (i) the magnitude of the locomotive’s linear acceleration when its speed is 14 m/s(ii) the direction of this acceleration at that point with respect to the locomotive’s radial acceleration (iii) the angular acceleration of the locomotive.
Certain stars are believed to be rotating at about 1 rot/s. If such a star has a diameter of 40 km, what is the linear speed of a point on the equator of the star?

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment