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A body of mass 2 kg is moving according to the equation for displacement at seconds as x(t) = pt^(2) + rt^(3). If p = 3 ms^(-1) , q = 4 ms^(-1) and r = 5 ms^(-1) the force acting after 2 sec is : |
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Answer» `136N` `(dx)/(dt)=p+2qt+3et^(2)` `a=(d^(2)x)/(dt^(2))=0+2q+6rt` ACCELERATION at `t = 2s = 0 + 2 xx 4 + 6 xx 5 xx 2` `= 68 ms^(-2)` `"Force" = ma = (2 xx 68) N` `= 136 N` HENCE .a. is the right choice |
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