A body of mass 2 kg is thrown vertically with K.E. 490 J. Taking g=10 m//s^(2). The height at which K.E. is reduced to half will be :

A body of mass 2 kg is thrown vertically with K.E. 490 J. Taking g=10

1.	A body of mass 2 kg is thrown vertically with K.E. 490 J. Taking g=10 m//s^(2). The height at which K.E. is reduced to half will be :
Answer» 10 m 12.25 m 20 m 25 m Solution :Loss in K.E= Gain in potential energy. ltvrgt `THEREFORE MGH=(1)/(2)(490)=245` `h=(245)/(2xx9.8)=12.25 m`

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A body of mass 2 kg is thrown vertically with K.E. 490 J. Taking g=10 m//s^(2). The height at which K.E. is reduced to half will be :

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