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A body of mass 2 kg makes an elastic collision with another body at rest and contiues to move in the original direction with a speed equal to one thrid of its original speed. Find the mass of the second body. |
Answer» Here, `m_(1)=2kg, u_(1)=upsilon,m_(2)=? u_(2)=0,` `upsilon_(1)=upsilon//2` As `upsilon_(1)=((m_(1)-m_(2))u_(1)+2m_(2)u_(2))/((m_(1)+m_(2)))` `:. (upsilon)/(2)=((2-m_(2))upsilon+2m_(2)xx0)/(2+m_(2))` or `2+m_(2)=2(2-m_(2))=4-2m_(2)` `3m_(2)=4-2=2` `m_(2)=(2)/(3)=0.67kg` |
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