1.

A body of mass `2kg` is moving with a velocity of `vecu=3hati+4hatj m//s`.A steady force `vecF=hati-2hatj N` begins to act on it. After four second, the body will be moving along.A. `X`-axis with a velocity of `2 m//s`B. `Y`-axis with a velocity of `5 m//s`C. `X`-axis with a velocity of `5 m//s`D. `Y`-axis with a velocity of `2 m//s`

Answer» Correct Answer - C
`v=u+at,F=ma`


Discussion

No Comment Found

Related InterviewSolutions