A body of mass 2kg is projected from the ground with a velocity 20ms^(-1) at an angle 30^(@) with the vertical. If t_(1) is the time in seconds at which the body is projected and t_(2) is the time in seconds at which it reaches the ground, the change in momentum in kgms^(-1) during the time (t_(2)-t_(1)) is

A body of mass 2kg is projected from the ground with a velocity 20ms^(

1.	A body of mass 2kg is projected from the ground with a velocity 20ms^(-1) at an angle 30^(@) with the vertical. If t_(1) is the time in seconds at which the body is projected and t_(2) is the time in seconds at which it reaches the ground, the change in momentum in kgms^(-1) during the time (t_(2)-t_(1)) is
Answer» 40 `40sqrt3` `50sqrt3` 60 Answer :B

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