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A body of mass `2kg` moving on a horizontal surface with an initial velocity of `4 ms^(-1)` comes to rest after `2` second. If one wants to keep this body moving on the same surface with a velocity of `4 ms^(-1)` the force required isA. 8 NB. 4 NC. zeroD. 2 N |
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Answer» Correct Answer - B Retarding force `=-ma=-m(v-u)//t` `=2(4-0)//2=4N` :. To keep velcity uniform force required = opposing force =4N |
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