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A particle moves in the x-y plane under is influence of a force such that its linear momentum is `vec(P)(t)=A[hat(i)cos (kt)-hat(j)sin (kt)]`, where A and k are constants Angle between the force and the momentum is:A. `0^(@)`B. `30^(@)`C. `45^(@)`D. `90^(@)` |
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Answer» Correct Answer - D `vec(F)=(dvec(P))/(dt)` |
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