InterviewSolution
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InterviewSolution
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A body of mass `3 kg` is under a constant force which causes a displacement `s` metre in it, given by the relation `s=(1)/(3)t^(2)`, where `t` is in seconds. Work done by the force in 2 seconds isA. `(19)/(5)J`B. `(5)/(19)J`C. `(3)/(8)J`D. `(8)/(3)J` |
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Answer» Correct Answer - D Here, `s=(1)/(3)t^(2)` `upsilon=(ds)/(dt)(2t)/(3)` `a=(dupsilon)/(dt)=(2)/(3)` `F=ma=3xx(2)/(3)=2N` When `t=2s, s=(t^(2))/(3)=(4)/(3)` As work done `=Fxxs :. W=2xx(4)/(3)=(8)/(3)J` |
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