A body of mass 5 kg collides elastically with a stationary body of mass 2.5 kg. After the collision, the 2.5 kg body begins to move with a kinetic energy of 8). Assuming the collision to be one-dimensional, the kinetic energy of the 5 kg body before collision is:

A body of mass 5 kg collides elastically with a stationary body of mas

1.	A body of mass 5 kg collides elastically with a stationary body of mass 2.5 kg. After the collision, the 2.5 kg body begins to move with a kinetic energy of 8). Assuming the collision to be one-dimensional, the kinetic energy of the 5 kg body before collision is:
Answer» 3 J 6 J 9 J 11J Solution :Here we know that the fraction of K.E. TRANSFERRED =`(4X)/((1+x)^2)=(4xx1/2)/((1+1//2)^2)` =8/9 This means that `("K.E of 2.5 KG after collison")/("K.E of 2.5 Kg before collison")=8//9` `:.` K.E of 5 kg before collison is `E_k=9//8xx8=9 J`

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A body of mass 5 kg collides elastically with a stationary body of mass 2.5 kg. After the collision, the 2.5 kg body begins to move with a kinetic energy of 8). Assuming the collision to be one-dimensional, the kinetic energy of the 5 kg body before collision is:

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