1.

A body of mass 5 kg explodes into 3 fragments having masses in the ratio of 2:2 : 1. The fragments with equal masses fly in merely far direction with speed 15 ms^(-1). What will be the velocity of lighter one ?

Answer»

15 m/s
`15sqrt(2)` m/s
30 m/s
`30sqrt(2)` m/s

Solution :Here, APPLYING law of conservation of momentum
`1xxv=sqrt((2xx15)^2+(2xx15)^2)=30sqrt2 MS^(-1)`.


Discussion

No Comment Found

Related InterviewSolutions