A body of mass 5 kg is acted upon by a constant forcevecF=(-3overset(wedge)(i)+6overset(wedge)(j))NIts initial velocity at t = 0 isvecu = (6overset(wedge)-2overset(wedge)ms^(-1) what is its velocity after 5s ? What is its magnitude ?

A body of mass 5 kg is acted upon by a constant forcevecF=(-3overset(w

1.	A body of mass 5 kg is acted upon by a constant forcevecF=(-3overset(wedge)(i)+6overset(wedge)(j))NIts initial velocity at t = 0 isvecu = (6overset(wedge)-2overset(wedge)ms^(-1) what is its velocity after 5s ? What is its magnitude ?
Answer» `(3overset(wedge)(i)+6overset(wedge)(j)),5ms^(-1)` `(2overset(wedge)(i)-2overset(wedge)(j)),2sqrt(2)ms^(-1)` `(3overset(wedge)(i)-4overset(wedge)(j)),5ms^(-1)` `(2overset(wedge)(i)-3overset(wedge)(j)),sqrt13ms^(-1)` Solution :Here `VECF=(-3hati+6hatj)N` `m=5kg` `:.VECA=(-3hati+6hatj)/(5)` Now `vecupsilon=vecu+vecat` `=(6hati-2hatj)+(-3hati+6hatj)/(5)xx5` `=(6hati-2hatj)-3hati+6hatj` `vecupsilon=(3hati+4hatj)` `\|upsilon\|=sqrt(9+16)=5ms^(-1)` HENCE (a) is the right choice.

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A body of mass 5 kg is acted upon by a constant forcevecF=(-3overset(wedge)(i)+6overset(wedge)(j))NIts initial velocity at t = 0 isvecu = (6overset(wedge)-2overset(wedge)ms^(-1) what is its velocity after 5s ? What is its magnitude ?

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