1.

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J.The height at which the kinetic energy of the body becomes half of the origibnal value is

Answer»

5 m
2.5 m
10 m
12.5 m

Solution :GAIN in P.E.=Loss in K.E.
`mgh=1/2xx490=245J`
`H=(2450)/(5xx9.8)=5M`


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