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A body of mass `5 kg` makes an elastic collision with another body at rest and continues to move in the original direction after the collision with a velocity equal to `1//10^(th)` of its original velocity. The mass of the second body isA. `4.09 kg`B. `0.5 kg`C. `5 kg`D. `5.09 kg` |
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Answer» Correct Answer - A `v_(1) = ((m_(1) -m_(2))/(m_(1) + m_(2))) u_(1)`. |
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