1.

A body of mass 50 kg is suspended using aspring balance inside a lift at rest. If the lift starts falling freely, the reading of the spring balance is

Answer»

`= 50 kg`
`gt 50 kg`
`lt 50 kg`
`=0`

Solution :Given,
MASS of the BODY, m = 50 kg
When LIFT is MOVING dowbn,
Scale reading `= (m(g-a))/(g)`
If lift starts falling freely, then a = g
Now, scale reading `= (m(g-g))/(g)=0`


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