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A body of mass `5g` is executing SHM with amplitude `10cm`, its velocity is `100cm//s`. Its velocity will be `50cm//s` at a displacement from the mean position equal toA. `5cm`B. `5sqrt3`C. `10sqrt3cm`D. `15sqrt3cm` |
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Answer» Correct Answer - B `A=10cm`, `v_(max)=100cm//s`, `v=50cm//s`, `x=?` `v_(max)=Aomegaimplies100=10omegaimpliesomega=10rad//s` `v=omegasqrt(A^2-x^2)` `50=10sqrt((10)^2-x^2)` `x=5sqrt3cm` |
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