InterviewSolution
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InterviewSolution
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A body of mass `m_(1)` collides elastically with another body of mass `m_(2)` at rest. If the velocity of `m_(1)` after collision is `(2)/(3)` times its initial velocity, the ratio of their masses is `:`A. `1:5`B. `5:1`C. `5:2`D. `2:5` |
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Answer» Correct Answer - B In all elastic collision, `upsilon_(1)=((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1)+((2m_(2))/(m_(1)+m_(2)))u_(2)` As second ball is initially at , `u_(2)=0` `:. upsilon_(1)=((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1)` As `upsilon_(1)=(2)/(3)u_(1)=((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1)` `:. 2m_(1)+2m_(2)=3m_(1)-2m_(2)` or `5m_(2)=m_(1)` or`(m_(1))/(m_(2))=(5)/(1)` |
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