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A body of mass `m` is atteched to the lower end of a spring whose upper end is fixed .The spring has negaligible mass .When the mass `m` is slightly puylled down and released it oscillation with a time period of `3 s` when the mass `m` is increased by `1kg` time period of oscillations becomes `5s` The value of `m` in `kg` isA. `(16)/(9)`B. `(9)/(16)`C. `(3)/(4)`D. `(4)/(3)` |
Answer» Correct Answer - B<br>`T = 2pi sqrt((m)/(k))`<br> `3 = 2 pi sqrt((m)/(k))` ….(i)<br> `5 = 2 pi sqrt((m+1)/(k))`….(ii)<br> `((1)^(2))/((2)^(2)) rArr (9)/(19) = (m)/(m + 1) rArr m = (9)/(16)` | |