A body of mass `m` is raised to a height 10 R from the surface of the earth, where R is the radius of the earth. Find the increase in potential energy. (G = universal constant of gravitational, M = mass of the earth and g= acceleration due to gravity)A. `(GMm)/(11R)`B. `(GMm)/(10R)`C. `(mgR)/(11G)`D. `(10GMm)/(11R)`

A body of mass `m` is raised to a height 10 R from the surface of the

1.	A body of mass `m` is raised to a height 10 R from the surface of the earth, where R is the radius of the earth. Find the increase in potential energy. (G = universal constant of gravitational, M = mass of the earth and g= acceleration due to gravity)A. `(GMm)/(11R)`B. `(GMm)/(10R)`C. `(mgR)/(11G)`D. `(10GMm)/(11R)`
Answer» Correct Answer - D At the surface of the earth, gravitational P.E. `U_(1)=-(GMm)/(R )` at a height `h = R + 10R = 11R` `U_(2)=-(GMm)/(11R)` `therefore U_(2)-U_(1)=-(GMm)/(11R)+(GMm)/(R )` `=(GMm)/(R )[1-(1)/(11)]` `=+(10)/(11)(GMm)/(R )`

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