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A body of mass `m` is rotated in a vertical circle with help of light string such that velocity of body at a point is equal to critical velocity at that point. If `T_(1), T_(2)` be the tensions in the string when the body is crossing the highest and the lowest positions then the following relation is correctA. `T_(2)-T_(1)=6 mg `B. ` T_(2)- T_(1)=4 mg `C. `T_(2)-T_(1)=3 mg`D. `T_(2)-T(1)=2 mg ` |
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Answer» Correct Answer - A `f_(1)=(mv^(2))/(r)-mg=0andT_(2)=(mv^(2))/(r)+mg` `=6 mg` `thereforeT_(2)-T_(1)=6 mg.` |
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