A body of mass 'm' is travelling with a velocity 'u' . When a constant retarding force 'F' is applied , it comes to rest after travelling a distance s_1 . If the initial velocity is 2u , with the same force F , the distance travelled before it comes to rest is s_(2) . then

A body of mass 'm' is travelling with a velocity 'u' . When a constant

1.	A body of mass 'm' is travelling with a velocity 'u' . When a constant retarding force 'F' is applied , it comes to rest after travelling a distance s_1 . If the initial velocity is 2u , with the same force F , the distance travelled before it comes to rest is s_(2) . then
Answer» `s_2=2s_1` `s_2=(s_1)/(2)` `s_2=s_1` `s_2 =4s_1` Solution :When the VELOCITY of the BODY become doubled the disatnce required to stop the body by same retarding FORCE become 4 TIMES. `:.S_2=4S_1`

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A body of mass 'm' is travelling with a velocity 'u' . When a constant retarding force 'F' is applied , it comes to rest after travelling a distance s_1 . If the initial velocity is 2u , with the same force F , the distance travelled before it comes to rest is s_(2) . then

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