1.

A body of mass of 2 kg moving with velocity 4 ms^( -1) horizontally stops after 2 s. If the body is to be kept in motion at the same surface with 4 ms^(-1) force needed is :

Answer»

IN
2N
4N
18 N

Solution :Here `a=(upsilon-u)/(1)=(0-4)/(2)=-2m//s^(2)`
`:.F=ma=2xx-2=-4N`
In order to keep the body MOVING with same speed Net FORCE should be zero i.e. `F. + (-4)= 0`
`impliesF. = 4N`THUS we have to apply 4N force. HENCE the correct choice is (c).


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