1.

A body projected along an inclined plane of angle of inclination 300 stops after covering a distance x_(1). The same body projected with the same speed stops after covering a distance x_(2) when the angle of inclination of the inclined plane is increased to 60^(@) the ratio of x_(1)//lx_(2) is

Answer»

`sqrt(2)`
2
`sqrt(3)`
1

Solution :HENCE APPLYING `v^(2)-u^(2)=2as`
In first case`0-u^(2)=2(-gsin30^@)x_(1)`
or `u^(2)=gx_(1)`
In SECOND case`0-u^(2)=2(-gsin60^@)x_(2)`
or `u^(2)=sqrt(3)gx_(2)`
or `gx_(1)=sqrt(3)gx_(2)`
or `x_(1)/x_(2)=sqrt(3)`


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