A body projected up reaches a point A in its path at the end of 4^(th) second and reaches the ground after 5 seconds from the starts .The height of A above the ground is (g=10 m//s^(2))

A body projected up reaches a point A in its path at the end of 4^(th)

1.	A body projected up reaches a point A in its path at the end of 4^(th) second and reaches the ground after 5 seconds from the starts .The height of A above the ground is (g=10 m//s^(2))
Answer» 19.6 m 30.6 m 11m 20 m Answer :D

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A body projected up reaches a point A in its path at the end of 4^(th) second and reaches the ground after 5 seconds from the starts .The height of A above the ground is (g=10 m//s^(2))

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