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A body rotates about a fixed axis with an angular acceleration `1rad//s^(2)` through what angle does it rotates during the time in which its angular velocity increases from `5rad//s` to `15rad//s`? |
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Answer» `omega^(2)=omega_(0)^(2)+2alphatheta` `thereforetheta=(omega^(2)-omega_(0)^(2))/(2alpha)=(225-25)/(2xx1)` `=100rad` |
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