1.

A rod of mass 2 kg ad length 2 m is rotating about its one end `O` wth an angular velocity `omega=4rad//s`. Find angular momentum of the rod about the axis rotation.

Answer» In pure rotational motion of a rigid body, component of total angualr momentum about axis of rotation is given by
`L=Iomega=((ml^(2))/(3))omega` `(I_(0)=(ml^(3))/(3))`
Substituting the value we have,
`L=((2)(2)^(2))/(3)(4)`
`=(32)/(3)kg-m^(2)//s`
direction of this component is perperdicular to paper inwards (from right hand rule), as the rotation clockwise.


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