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A body weighs 20gm in air, 12gm in liquid and 10gmin water. Calculate the relative density of the liquidand the body. |
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Answer» Weight of the body in air = 20gf ( Wa) Weight of the body in water = 10gf ( Ws) Weight of the body in liquid =12gf ( Wl) Now, The loss of weight in the water = 20 - 10 or, 10 gf So the relative density of the body is = Wa / ( wa - ws ) = 20 / 10 = 2 2) The weight loss in liquid = 20 - 12 or, 8 gf So the relative density of the liquid is =( Wa - Wl ) / ( Wa - Ws ) = 8 / 10 = 0.8 |
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