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A body weighs 20gm in air, 12gm in liquid and 10gmin water. Calculate the relative density of the liquidand the body. |
Answer» <p>Weight of the body in air = 20gf ( Wa)</p><p>Weight of the body in water = 10gf ( Ws)</p><p>Weight of the body in liquid =12gf ( Wl)</p><p>Now,</p><p>The loss of weight in the water = 20 - 10 or, 10 gf</p><p>So the relative density of the body is = Wa / ( wa - ws )</p><p>= 20 / 10</p><p>= 2</p><p>2) The weight loss in liquid = 20 - 12 or, 8 gf</p><p>So the relative density of the liquid is =( Wa - Wl ) / ( Wa - Ws )</p><p>= 8 / 10</p><p>= 0.8</p> | |