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InterviewSolution
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A body weighs 72 N on the surface of the earth. What is the gravitational force on it due to earth at a height equal to half the radius of the earth from the surfaceA. 16 NB. 28 NC. 32 ND. 72 N |
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Answer» Correct Answer - C ( c) Weight of the body on the surface of the earth = mg= 72 N Acceleration due to gravity at height h is `g_(h)=(gR_(E)^(2))/((R_(E)+h)^(2))=(gR_(E)^(2))/((R_(E)+(R_(E))/(2))^(2))=(4)/(9)g( :.h=(R_(E))/(2))` Gravitational force on body at height h is `F=mg_(h)=mxx(4)/(9) g= (4)/(9)xx mg=(4)/(9)xx72=32 N` |
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