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A body weighs more at poles than at the equator of earth. Why ? |
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Answer» Earth is flattened at poles and bugled out at equator. Thereforce, polar radius `(R_(p))` is smaller than equatorial radius `(R_(e))`. As `g=(GM)/R^(2)`, and `R_(p) lt R_(e)` therefore, `g_(p) gt g_(e)` As `(W_(p))/(W^(e))=(mg_(p))/(mg_(e))` and `g_(p) gt g_(e) :. W_(p) gt W_(e)`. |
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