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A body weight 45 kg wt on the surface of earth. Its weight on the surface of Mars will be [Mass of Mars = (1/9) mass of earth, Radius of Mars = (1/2) Radius of earth]A. 25 kg wtB. 20 kg wtC. 30 kg wtD. 40 kg wt |
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Answer» Correct Answer - b `F_(1)=(GM_(1)m)/(R_(1)^(2)) and F_(2)=(GM_(2)m)/(R_(2)^(2))` `therefore" "(F_(2))/(F_(1))=(M_(2))/(M_(1))xx(R_(1)^(2))/(R_(2)^(2))` |
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