1.

A body when released from the top of a tower of height h reaches the ground in time T. At what time it is at a height h/2above the ground?

Answer»

`T/2`
`T/4`
`T/(SQRT(2))`
`sqrt(2T)`

Solution :`h=(1)/(2)g t^(2)`
Now `(h)/(2)=(1)/(2) g t^(2):. (1)/(2)((1)/(2)g t^(2))=(1)/(2) g t^(2)implies t=(t)/(sqrt(2))`


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