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A bolck of mass `10 kg` is moving in x-direction with a constant speed of `10 m//s`. it is subjected to a retardeng force `F=-0.1 x J//m`. During its travel from `x =20m` to `x =30 m`. Its final kinetic energy will be .A. `475 J`B. `450 J`C. `275 J`D. `250 J` |
Answer» Correct Answer - A `K_(f)-K_(i) =W =int Fdx` `:. K_(f) =K_(i) + int_(20)^(30)(-0.1x)dx` `1/2 xx 10 xx (10)^(2)-[0.1(x^(2))/(2)]_(20)^(30)` `475 J`. |
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