A bomb at rest at the summit of a cliff breaks into two equal fragments. One of the fragments attains a horizontal velocity of 20sqrt(3) ms^(-1). The horizontal distance between the two fragments, when their displacement vectors is inclined at 60^@ relative to each other is (g = 10ms^(-2))

A bomb at rest at the summit of a cliff breaks into two equal fragment

1.	A bomb at rest at the summit of a cliff breaks into two equal fragments. One of the fragments attains a horizontal velocity of 20sqrt(3) ms^(-1). The horizontal distance between the two fragments, when their displacement vectors is inclined at 60^@ relative to each other is (g = 10ms^(-2))
Answer» `40 SQRT(3) m` `80 sqrt(2) m` `120 sqrt(3) m` `480 sqrt(3)m` Answer :D

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A bomb at rest at the summit of a cliff breaks into two equal fragments. One of the fragments attains a horizontal velocity of 20sqrt(3) ms^(-1). The horizontal distance between the two fragments, when their displacement vectors is inclined at 60^@ relative to each other is (g = 10ms^(-2))

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