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A bomb moving with velocity 40 hat(i)+50hat(j)+25hat(k) m/s explodes into pieces of mass ratio 1 : 4. If the small piece goes out with velocity 200hat(i)+70 hat(j)-15hat(k)m//s, find the velocity of larger piece after explosion. |
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Answer» Solution :LET 5M be MASS of bomb. The LARGEST piece will have mass 4m. Using principle of momentum conservation, `5m(40hat(i)+50hat(j)-25hat(k))=m(200hat(i)+70hat(j)-15hat(k))+4m vec(v)` Which gives `vec(v)=(180hat(j)+140hat(k))/(4)=(45hat(j)+35hat(k))` |
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