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A bomb of 1 kg is thrown vertically up with speed 100 m/s. After 5 seconds, it explodes into two parts. One of mass 400 gm goes down with speed 25 m/s. What will happen to the other part just after explosion |
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Answer» Solution :After 5 sec, VELOCITY of bomb V=u-gt =100 - 10 `xx 5= 50` m/s `therefore` Initial momentum before explosion `=1 xx 50 kg ms^(-1)` From momentum conservation `,1 xx 50 = -0.4 xx 25 + 0.6 v` `therefore v. = 100 m//s` UPWARDS |
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