1.

A bomb of 12 kg explodes into two parts 4 kg and 8 kg. The velocity of 8 kg mass is 6 ms^(-1).The the other is :

Answer»

4.8 J
288 J
48 J
24 J

Solution :Initial momentum= FINAL momentum.
`12xx0=8xx6+4v`
`IMPLIES v=-12 ms^(-1)`
`:. K.E=(1)/(2)4(-12)^(2)=288 J`


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