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A bomb of 12 kg explodes into two parts 4 kg and 8 kg. The velocity of 8 kg mass is 6 ms^(-1).The the other is : |
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Answer» Solution :Initial momentum= FINAL momentum. `12xx0=8xx6+4v` `IMPLIES v=-12 ms^(-1)` `:. K.E=(1)/(2)4(-12)^(2)=288 J` |
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