1.

A bomb of mass 16 kg at rest explodes into two pieces of masses 4 kg and 12 kg. The velocity of the 12 kg mass is 4 ms^(-1). The kinetic energy of the other mass is :

Answer»

144 J
288 J
192 J
96 J

Solution :INITIAL MOMENTUM = FINAL momentum
`16xx0=4v_1+12xx4`
`v_1=-12m//s`
`:.` K.E. =`1/2m_1v_1^2=1/2xx4(-12)^2=288J`.


Discussion

No Comment Found

Related InterviewSolutions