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InterviewSolution
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A bomb of mass `16 kg ` at rest explodes into two pieces of masses `4kg` and `12kg`. If KE of `4 kg` mass is `288 J`, what is the velocity (in `ms^(-1)` of the other piece of `12 kg` ? |
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Answer» Here, `m_(1)=4 kg, m_(2)=12 kg ` `E_(1)=(1)/(2) m_(1)upsilon_(1)^(2)` `288=(1)/(2) xx4 upsilon_(1)^(2), upsilon_(1)=sqrt((288)/( 2))=12 m//s` According to principle of conservation of linear momentum, `m_(1)upsilon_(1)+m_(2)upsilon_(2)=0` `upsilon_(2)=(-m_(1)upsilon_(1))/( m_(2))`, `upsilon_(2)=(-4xx12)/( 12)`=-4 m//s` |
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