InterviewSolution
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InterviewSolution
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A bomb of mass `3.0 kg` explodes in air into two pieces of masses `2.0 kg` and `1.0 kg`. The smaller mass goes at a speed of `80 m//s`. The total energy imparted to the two fragments is :A. `1.07 kJ`B. `2.14 kJ`C. `2.4 kJ`D. `4.8 kJ` |
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Answer» Both fragments will posses the equal linear momentum `m_(1) v_(1) = m_(2) v_(2) implies 1 xx 80 = 2 xx v_(2) implies v_(2) = 40 m//s` `:.` Total energy of system ` = (1)/(2) m_(1) v_(1) + (1)/(2) m_(2) v_(2)^(2)` `= (1)/(2) xx 1 xx (80)^(2) + (1)/(2) xx 2 xx (40)^(2)` `= 4800 J = 4.8 kJ` |
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