A box contains 5 red balls, 8 green balls and 10 pink balls. A ball is

1.	A box contains 5 red balls, 8 green balls and 10 pink balls. A ball is drawn at random from the box. What is the probability that the ball drawn is either red or green.
Answer» m(S) = 5 + 8 + 10 = 23 A= Red or Green, n(A)= 5 + 8 =13 P(A) = \(\frac{n(A)}{n(S)} = \frac{13}{23}\)

A box contains 5 red balls, 8 green balls and 10 pink balls. A ball is drawn at random from the box. What is the probability that the ball drawn is either red or green.

Answer»

m(S) = 5 + 8 + 10 = 23

A= Red or Green, n(A)= 5 + 8 =13

P(A) = \(\frac{n(A)}{n(S)} = \frac{13}{23}\)

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A box contains 5 red balls, 8 green balls and 10 pink balls. A ball is drawn at random from the box. What is the probability that the ball drawn is either red or green.

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