A box contains 5 red marbles, 8 white marbles and 4 green marbles. One

1.	A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be (i) red ? (ii) white ? (iii) not green ?
Answer» A box contains 5 red marbles, 8 white marbles and 4 green marbles. ∴ Total number of marbles, n(S) = 5 + 8 + 4 = 17 (i) Probability that the 1 red marble drawn is n(A) = 5 ∴ Probability, P(A) = \(\frac{n(A)}{n(S)} = \frac{5}{17}\) (ii) Possibility that 1 white marble drawn, n(B) = 8 ∴ Probability, P(B) = \(\frac{n(B)}{n(S)} = \frac{8}{17}\) (iii) Possibility that 1 not green marble ? P(C) = 17 – 4 = 13 (∵ Except 4 green marbles) ∴ Probability, P(C) = \(\frac{n(c)}{n(S)} = \frac{13}{17}\)

A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be (i) red ? (ii) white ? (iii) not green ?

Answer»

A box contains 5 red marbles, 8 white marbles and 4 green marbles.

∴ Total number of marbles, n(S)

= 5 + 8 + 4 = 17

(i) Probability that the 1 red marble drawn is n(A) = 5

∴ Probability, P(A) = \(\frac{n(A)}{n(S)} = \frac{5}{17}\)

(ii) Possibility that 1 white marble drawn, n(B) = 8

∴ Probability, P(B) = \(\frac{n(B)}{n(S)} = \frac{8}{17}\)

(iii) Possibility that 1 not green marble ?

P(C) = 17 – 4 = 13 (∵ Except 4 green marbles)

∴ Probability, P(C) = \(\frac{n(c)}{n(S)} = \frac{13}{17}\)

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A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be (i) red ? (ii) white ? (iii) not green ?

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