A box contains S defective and 15 non defective bulbs. Two bulbs are c

1.	A box contains S defective and 15 non defective bulbs. Two bulbs are chosen at random. Find the probability that both the bulbs are non- defective.
Answer» Total = 5 + 15 = 20, n(S) = 20c₂ = \(\frac{20\times19}{2\times1} = 190\) Let A = both bulbs are non-defective n(A)= 15c₂= \(\frac{14\times15}{2\times 1} = 105\) P(A) = \(\frac{n(A)}{n(S)}\) = \(\frac{105}{190}\) = \(\frac{21}{38}\)

A box contains S defective and 15 non defective bulbs. Two bulbs are chosen at random. Find the probability that both the bulbs are non- defective.

Answer»

Total = 5 + 15 = 20,

n(S) = 20c₂ = \(\frac{20\times19}{2\times1} = 190\)

Let A = both bulbs are non-defective

n(A)= 15c₂= \(\frac{14\times15}{2\times 1} = 105\)

P(A) = \(\frac{n(A)}{n(S)}\) = \(\frac{105}{190}\) = \(\frac{21}{38}\)

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A box contains S defective and 15 non defective bulbs. Two bulbs are chosen at random. Find the probability that both the bulbs are non- defective.

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