A box has 390 bulbs. Out of this 26 are defective. A bulb is chosen at

1.	A box has 390 bulbs. Out of this 26 are defective. A bulb is chosen atrandom. Find the probability of the bulbs chosen not being defective.[A] 1/15[B] 14/15[C] 3/20[D] 2/20
Answer» Step-by-step EXPLANATION: A box has 390 BULBS. Out of this 26 are defective Bulb chosen, not being defective =390−26=364 The probability is P(E)= 390 364 = 15 14

A box has 390 bulbs. Out of this 26 are defective. A bulb is chosen atrandom. Find the probability of the bulbs chosen not being defective.[A] 1/15[B] 14/15[C] 3/20[D] 2/20

Answer»

Step-by-step EXPLANATION:

A box has 390 BULBS.

Out of this 26 are defective

Bulb chosen, not being defective =390−26=364

The probability is P(E)=

390

364